4x^2-16x-236=0

Solution for 4x^2-16x-236=0 equation:

4x^2-16x-236=0

a = 4; b = -16; c = -236;
Δ = b2-4ac
Δ = -162-4·4·(-236)
Δ = 4032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4032}=\sqrt{576*7}=\sqrt{576}*\sqrt{7}=24\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24\sqrt{7}}{2*4}=\frac{16-24\sqrt{7}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24\sqrt{7}}{2*4}=\frac{16+24\sqrt{7}}{8}
$